Question

помогите, через дискриминант​

Answer 1

Ответ:

x₁ = 3

x₂ = -1

Объяснение:

x²-2x-3 = 0

D = b²- 4ac = 4+12 = 16

x₁ = (-b+√D)/2a = (2+4)/2 = 6/2 = 3

x₂ = (-b-√D)/2a = (2-4)/2 = -2/2 = -1

Answer 2

Ответ:

$x^2-2x-3=0\\\\D=b^2-4ac=(-2)^2-4\cdot 1\cdot (-3)=4+12=16\\\\x_{1,2}=\dfrac{-b\pm \sqrt{D}}{2a}=\dfrac{2\pm \sqrt{16}}{2}=\dfrac{2\pm 4}{2}\\\\x_1=-1\ ,\ x_2=3$