Question

Решите пожалуйста !!!

Answer 1

$\left\{\begin{array}{l}9x-3>6x\\\dfrac{2+x}{3}-\dfrac{6-x}{2}\leq 6\ |\cdot 6\end{array}\right\ \ \left\{\begin{array}{l}9x-6x>3\\2(2+x)-3(6-x)\leq 36\end{array}\right\ \ \left\{\begin{array}{l}3x>3\\4+2x-18+3x\leq 36\end{array}\right$

$\left\{\begin{array}{l}x>1\\5x\leq 50\end{array}\right\ \ \left\{\begin{array}{ccc}x>1\\x\leq 10\end{array}\right\ \ \ \Rightarrow \ \ \ 1<x\leq 10\\\\\\Otvet:\ \ x\in (\ 1\, ;\, 10\ ]\ .$