Question

решите уравнение 1) 3 (x*2-2)-3x+7-3 (x*2-2x)=0 . 2)-(x*2-2)-0.3x+7x+(x*2-0.2x)=0

Answer 1

1)

$3(x^{2} -2)-3x+7-3(x^{2} -2x)=0\\3x^{2} -6-3x+7-3x^{2} +6x=0\\3x+1=0\\x = -\frac{1}{3}$

2)

$-(x^{2} -2)-0.3x+7x+(x^{2} -0.2x)=0\\-x^{2} +2-0.3x+7x+x^{2} -0.2x=0\\6.5x+2=0\\x=-\frac{2}{6.5} =-\frac{4}{13}$