Question

{20х+40<=0
{2/9-4/27х>0​

Answer 1

Ответ:

$\left \{ {{20x+40\leq 0} \atop {\frac{2}{9} -\frac{4}{27}x >0}} \right. \\\left \{ {{20x\leq-40 } \atop {-\frac{4}{27}x>-\frac{2}{9} }} \right.\\\left \{ {{x\leq-2 } \atop {x<\frac{2*27}{9*4} }} \right.\\\left \{ {{x\leq-2 } \atop {x<\frac{3}{2} }}$

⇒х∈(-∞;-2]