Question

((4^2)*(2^-2)-2^2*(4^-2))/2^-4​
Фото прикреплено

Answer 1

$\frac{4^{2}*2^{-2}-2^{2}*4^{-2}}{2^{-4}}=\frac{16*\frac{1}{4}-4*\frac{1}{16}}{\frac{1}{16}}=(4-\frac{1}{4})*16=\frac{15}{4}*16=15*4=60\\\\Otvet:\boxed{60}$