Question

помогите пожалуйста
$( \frac{6a + c}{ {a}^{2} - 6ac} + \frac{6a - c}{ {a}^{2} + 6ac}) \times \frac{ {a}^{2} - 36 {c}^{2} }{ {a}^{2} + {c}^{2} }$
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Answer 1

$(\frac{6a+c}{a^{2} - 6ac} +\frac{6a-c}{a^{2} + 6ac}) *\frac{a^{2} - 36c^{2}}{a^{2}+c^{2}} =(\frac{6a+c}{a(a - 6c) } +\frac{6a-c}{a(a + 6c)})*\frac{a^{2} - 36c^{2}}{a^{2}+c^{2}}=(\frac{(6a+c) (a+6c)+(6a-c) (a-6c) }{a(a - 6c) (a+6c)} )*\frac{a^{2} - 36c^{2}}{a^{2}+c^{2}}=\frac{6a^{2}+ac+36ac+6c^{2}+6a^{2} - ac-36ac+6c^{2} }{a(a^{2}-36c^{2})} *\frac{a^{2} - 36c^{2}}{a^{2}+c^{2}}=\frac{12(a^{2}+c^{2})}{a(a^{2}-36c^{2})}*\frac{a^{2} - 36c^{2}}{a^{2}+c^{2}}= \frac{12}{a}$