Question

а)7√3+2√27-√75= б)2√7*√21= в)(2√2-√50)·√2= г)(4√80-√125)÷√5= д)6√х-$frac{2}{3}$√9х+10√$frac{x}{4}$= е)(√аб+√б)÷√б=

Answer 1

а)7√3+2√27-√75=7√3+2√3*9-√3*25=√3(7+√9-√25)=√3(7+9-5)=11√3
б)2√7*√3*7=2*7*√3=14√3
в)(2√2-√2*25)·√2=√2(2-5)·√2=2*(-3)=-15
д)6√х-*3√х+10* 1/2√х= 6√х-2√х+5√х= 9√х

е)(√аб+√б)÷√б=√б(√а+1)÷√б=(√а+1)