Question

$(3x + 1) ^{2} + 5 \times (3x + 1) - 36 = 0$
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Answer 1

Ответ:

Объяснение:

9x^2+6x+1+15x+5-36=0

9x^2+21x-30=0 | : 3

3x^2+7x-10=0

D=49-4*3*(-10)=49+120=169=13^2

x1= (-7-13) / (3*2) = -20/6 = -10/3 = -3 1/3

x1= (-7+13) / (3*2) = 8/6 = 4/3 = 1 1/3