Question

сократите дробь 16-8x+x^2/(x-4)^3​

Answer 1

$\frac{16-8x+x^{2} }{(x-4)^3}=\frac{x^2-8x+16 }{(x-4)^3}= \frac{(x-4)^2}{(x-4)^3}=\frac{1}{x-4}$