Question

d =3 s2= 19 S8 -? (an)= арифметическая прогрессия​

Answer 1

$d=3\\\\S_{2}=a_{1}+a_{2}=a_{1}+a_{1}+d=2a_{1}+d\\\\2a_{1}+d=19\\\\2a_{1}=19-d=19-3=16\\\\a_{1} =8\\\\S_{8}=\frac{2a_{1}+7d }{2}*8=(2a_{1}+7d)*4=(2*8+7*3)*4= 148\\\\Otvet:\boxed{S_{8}=148}$