Question

X² - 7x + 12
$\geqslant$
20​

Answer 1

Ответ:

${x}^{2} - 7x + 12 \geqslant 20 \\ {x}^{2} - 7x - 8 \geqslant 0 \\ {x}^{2} - 7x - 8 = 0 \\ (x + 1)(x - 8) = 0 \\ x1 = - 1 \\ x2 = 8$

Х с (-♾️;-1]и[8;+♾️)