Question

алгебра. Решить неравенство ​

Answer 1

$a)\ \left\{\begin{array}{ccc}1<2x-1<5\\2\leq 3x-1<11\end{array}\right\ \ \left\{\begin{array}{ccc}2<2x<6\\3\leq 3x<12\end{array}\right\ \ \left\{\begin{array}{ccc}1<x<3\\1\leq x<4\end{array}\right\ \ \Rightarrow \ \ 1<x<3$

$b)\ \left\{\begin{array}{ccc}10\leq 4x-2<26\\3<2x-1<11\end{array}\right\ \ \left\{\begin{array}{ccc}12\leq 4x<28\\4<2x<12\end{array}\right\ \ \left\{\begin{array}{ccc}3\leq x<7\\2<x<6\end{array}\right\ \ \Rightarrow \ \ 3\leq x<6$

$c)\ \ \left[\begin{array}{ccc}1<x<3\\3\leq x<6\end{array}\right\ \ \Rightarrow \ \ \ 1<x<6\ \ ,\ \ \ \ x\in (\, 1\, ;\, 6\, )$

Answer 2

Решение на фото/////