Question

Все на рисунке!!!!!!!!!!!

Answer 1

$x^2+(x^2-5)(x^2-4)=4\Leftrightarrow x^2+x^4-9x^2+20-4=0\\x^4-8x^2+16=0\Leftrightarrow \left ( x^2-4 \right )^2=0\Rightarrow x=\pm 2\\x=2\Rightarrow 2^{27}+2^{27}+14+13\nless 0\\x=-2\Rightarrow -14+13=-1< 0$

Ответ:x=-2