Question

решите уравнение (х-1)^2-(2х-1)^2=0​

Answer 1

Объяснение:

${(x - 1)}^{2} - {(2x - 1)}^{2} = {x}^{2} - 2x + 1 - (4 {x}^{2} - 4x + 1) = {x}^{2} - 2x + 1 - 4 {x}^{2} + 4x - 1 = - 3 {x}^{2} + 2x = 0 \\ - x(3x - 2) = 0 \\ x = 0 \\ 3x - 2 = 0 \\ 3x = 2 \\ x = \frac{2}{3}$

Answer 2

$(x-1)^{2} -(2x-1)^{2} =0$

$(x-1-2x+1)(x-1+2x-1) =0$

$-x(3x-2) =0$

[ $-x = 0$   =>   $x = 0$

[ $3x - 2 = 0$     =>     $3x = 2$    =>    $x = \frac{2}{3}$

Ответ : 0 , 2/3