Question

Даю 35 баллов помогите

Answer 1

$1)\frac{3x}{(x-1)(x+1)}-\frac{2-3x}{x-1}+\frac{4+x}{x+1}-6=0\\\\\frac{3x-(2-3x)(x+1)+(4+x)(x-1)-6(x^{2}-1) }{x^{2}-1 }=0\\\\\frac{3x-2x-2+3x^{2}+3x+4x-4+x^{2}-x-6x^{2}+6}{x^{2}-1 }=0\\\\\frac{-2x^{2}+7x }{x^{2}-1 }=0\\\\\left \{ {{-2x^{2}+7x=0 } \atop {x^{2}-1\neq0 }} \right.\\\\\left \{ {{x(2x-7)=0} \atop {x\neq-1; x\neq1 }} \right. \\\\x_{1}=0\\\\2x-7=0\\\\x_{2}=3,5\\\\Otvet:\boxed{0;3,5}$

$2)\frac{2x}{(5-x)(5+x)}+\frac{3x+5}{5-x}+\frac{2x+5}{5+x}-2=0\\\\\frac{2x+(3x+5)(5+x)+(2x+5)(5-x)-2(25-x^{2})}{25-x^{2} }=0\\\\\frac{2x+15x+3x^{2}+25+5x+10x-2x^{2}+25-5x-50+2x^{2}}{25-x^{2} }=0\\\\\frac{3x^{2}+27x }{25-x^{2} }=0\\\\\left \{ {{3x^{2}+27x=0 } \atop {25-x^{2}\neq0}} \right.\\\\\left \{ {{x^{2}+9x=0 } \atop {x\neq5;x\neq -5 }} \right.\\\\x(x+9)=0\\\\x_{1}=0\\\\x_{2}=-9\\\\Otvet:\boxed{0;-9}$