Question

Помогите пожалуйста​

Answer 1

$log .p^{2} (ab) = 10\\log.p^{2} (\frac{a}{b} ) = 8$

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$0.5 log.p(ab) = 10\\0.5 log.p(\frac{a}{b} )=8$

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$0.5(log.p(a)+log.p(b)) = 10\\0.5(log.p(a)-log.p(b)) = 8$

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$0.5log.p(a)+0.5log.p(b)) = 10\\0.5log.p(a)-0.5log.p(b) = 8$  +

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$0.5log.p(a)+0.5 log.p(a)= 10+8\\log.p(a) = 18$

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$9 + 0.5log.p(b) = 10\\0.5 log.p(b) = 1\\log.p(b) = 2$

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$\frac{log.p(a)}{log.p(b)} = \frac{18}{2} =\frac{9}{1}$

Ответ : 9/1