Question

помогите плиз математика жесть ​

Answer 1

Ответ:

Пошаговое объяснение:

$\frac{4}{b^{2} +b} + \frac{2}{b^{2} -1 } + \frac{-1}{b^{2}-b } * (1+2b+b^{2} )\\\frac{4}{b(b+1)} + \frac{2}{(b-1)(b+1) } + \frac{-1}{b(b-1) } = \frac{4b-4+2b-b-1}{b(b-1)(b+1)} =\frac{5b-5}{b(b-1)(b+1)} = \frac{5(b-1)}{b(b-1)(b+1)} =\\\frac{5}{b(b+1)}\\\\\frac{5}{b(b+1)} * (1+2b+b^{2} ) = \frac{5}{b(b+1)} * (b+1)^{2} =\frac{5(b+1)}{b}\\\frac{5(b+1)}{b}= \frac{5(5/6 + 1)}{5/6} = 5\frac{25}{6} :\frac{5}{6} = \frac{55}{6} * \frac{6}{5} = 11$

$\left \{ {{2x+y=6} \atop {xy=4}} \right. \left \{ {{y=6-2x} \atop {xy=4}} \right. \left \{ {{y=6-2x} \atop {x(6-2x)=4}} \right. \left \{ {{y=6-2x} \atop {6x-2x^{2} =4}} \right. \\6x-2x^{2} =4\\2x^{2} -6x+4=0\\x^{2} -3x+2=0\\x=1 \ \ \ \ \ \ x=2$

$y=6-2*1\\y=4\\y=6-2 * 2\\y=2$

x₁+x₂+y₁+y₂=1+2+4+2=9

Дальше плохо вижу задания