Question

Спростити вираз !!!!! Дуже терміново

Answer 1

Ответ:√а

Объяснение:1) (√а+1)/(√а-1)-(4√а/(а-1))=(а+1-4√а+2√а)/(а-1)=(√а-1)²/(а-1)

=(√а-1)/(√а+1)

2) ((√а-1)/(√а+1)):((√а-1)/(√а*(√а+1))=

(√а*(√а+1)*(√а-1))/((√а+1)*(√а-1))=√а

Answer 2

$(\frac{\sqrt{a}+1 }{\sqrt{a}-1 } -\frac{4\sqrt{a} }{a-1}) : \frac{\sqrt{a}-1 }{a+\sqrt{a} }= (\frac{\sqrt{a}+1 }{\sqrt{a}-1 } -\frac{4\sqrt{a} }{(\sqrt{a}-1)(\sqrt{a}+1 }) \cdot \frac{a+\sqrt{a} }{\sqrt{a}-1 }=$

$\frac{(\sqrt{a}+1)^2-4\sqrt{a} }{(\sqrt{a}-1)(\sqrt{a}+1 ) } \cdot \frac{\sqrt{a}\cdot (\sqrt{a}+1) }{\sqrt{a}-1 }= \frac{a+2\sqrt{a}+1-4\sqrt{a} }{\sqrt{a}-1} \cdot \frac{\sqrt{a} }{\sqrt{a}-1 }= \frac{a-2\sqrt{a}+1 }{\sqrt{a}-1} \cdot \frac{\sqrt{a} }{\sqrt{a}-1 }=\\\\=\frac{(\sqrt{a}-1)^2 }{(\sqrt{a}-1)^2} \cdot \sqrt{a} =\sqrt{a}$