Question

$\frac{4 - m}{m - 3} + \frac{2m - 5}{3 - m} =$
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Answer 1

$\frac{4-m}{m-3} +\frac{2m-5}{3-m}= \frac{4-m}{m-3} -\frac{2m-5}{m-3}=\frac{(4-m)-(2m-5)}{m-3}=\frac{4-m-2m+5}{m-3}=\frac{9-3m}{m-3}=\frac{-3(m-3)}{m-3}=\\\\= -3$