Question

пожалуста помогите !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Answer 1

Ответ:

1.

Пошаговое объяснение:

$(\frac{a\sqrt{a}+b\sqrt{b}}{\sqrt{a}+\sqrt{b}} -\sqrt{ab}):(a-b)+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=\\ \\ =(\frac{a\sqrt{a}+b\sqrt{b}-\sqrt{ab}(\sqrt{a}+\sqrt{b})}{\sqrt{a}+\sqrt{b}}):(a-b)+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=\\ \\=(\frac{a\sqrt{a}+b\sqrt{b}-\sqrt{ab}\sqrt{a}-\sqrt{ab}\sqrt{b})}{\sqrt{a}+\sqrt{b}}):(a-b)+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=\\ \\=(\frac{a\sqrt{a}+b\sqrt{b}-a\sqrt{b}-b\sqrt{a}}{\sqrt{a}+\sqrt{b}}):(a-b)+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=$

$(\frac{(a\sqrt{a}-a\sqrt{b})+(b\sqrt{b}-b\sqrt{a})}{\sqrt{a}+\sqrt{b}}):(a-b)+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=\\ \\=(\frac{a(\sqrt{a}-\sqrt{b})+b(\sqrt{b}-\sqrt{a})}{\sqrt{a}+\sqrt{b}}):(a-b)+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=\\ \\=(\frac{a(\sqrt{a}-\sqrt{b})-b(\sqrt{a}-\sqrt{b})}{\sqrt{a}+\sqrt{b}}):(a-b)+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=\\ \\=(\frac{(\sqrt{a}-\sqrt{b})(a-b)}{\sqrt{a}+\sqrt{b}}):(a-b)+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=$

$=\frac{(\sqrt{a}-\sqrt{b})(a-b)}{(\sqrt{a}+\sqrt{b})(a-b)}+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=\\ \\=\frac{\sqrt{a}-\sqrt{b}}{\sqrt{a}+\sqrt{b}}+\frac{2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=\\ \\=\frac{\sqrt{a}-\sqrt{b}+2\sqrt{b}}{\sqrt{a}+\sqrt{b}}=\\ \\=\frac{\sqrt{a}+\sqrt{b}}{\sqrt{a}+\sqrt{b}}=1$