Question

Помогите пожалуйста
$\frac{ {3}^{9} \times {12}^{19} + 15 \times {4}^{9} \times {9}^{4} }{ {6}^{9} \times {2}^{10} + {12}^{10} } \times {( \frac{3}{4} )}^{ - 1}$
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Answer 1

$.......=\frac{3^{9}*3^{19} *(2^{2}) ^{19} +3*5*(2^{2})^{9}*(3^{2})^{4} }{2^{9}*3^{9}*2^{10}+3^{10} *(2^{2})^{10} }*\frac{2^{2} }{3} =\frac{3^{28}*2^{38}+5*3^{9}*2^{18}}{2^{19}*3^{9}+2^{20}*3^{10}}*\frac{2^{2} }{3} =\\ \\ \frac{2^{18} *3^{9}*(2^{20} +5)}{2^{19}*3^{9}*(1+2*3)} *\frac{2^{2} }{3} =\frac{2*(2^{20}+5) }{7*3} =\frac{2^{21}+5 }{21}$