Question

Помогите пожалуйста!!!

Answer 1

Пошаговое объяснение:

$y=\frac{2*(1+x^4)}{(1-x^2)}\\y'=(\frac{2*(1+x^4)}{(1-x^2)})'=\frac{2*(4x^3*(1-x^2)-(1+x^4)*(1-x^2)') } {(1-x^2)^2}=\frac{2*(4x^3-4x^5-(1+x^4)*(-2x)}{(x^2-1)^2})=\\ =\frac{2*(4x^3-4x^5+2x+2x^5)}{(x^2-1)^2}= \frac{2*(4x^3-2x^5+2x)}{(x^2-1)}=\frac{-4x^5+8x^3+4x}{(x^2-1)}.$