Question

Упростите выражения:
а)(2) `(sqrt(x+2sqrt(x-1)))/(sqrt(x-1)+1)`;
б)(2) `((sqrt2+1)/(1+sqrt2+sqrtx)+(sqrt2-1)/(1-sqrt2+sqrtx))*(sqrtx-1/(sqrtx)+2)`.

Answer 1

$a.) \frac{\sqrt{x+2\sqrt{x-1}}}{\sqrt{x-1}+1}\\b.) (\frac{\sqrt{2}+1}{1+\sqrt{2}+\sqrt{x}} + \frac{\sqrt{2}-1}{1-\sqrt{2}+\sqrt{x}})(\sqrt{x}-\frac{1}{\sqrt{x}+2})\\\\a.) \frac{\sqrt{x+2\sqrt{x-1}}}{\sqrt{x-1}+1}\\\frac{\sqrt{x+1-1+2\sqrt{x-1}}}{\sqrt{x-1}+1}\\\frac{\sqrt{x-1+2\sqrt{x-1}+1}}{\sqrt{x-1}+1}\\\frac{\sqrt{(\sqrt{x-1})^{2}+2\sqrt{x-1}+1}}{\sqrt{x-1}+1}\\\frac{\sqrt{(\sqrt{x-1}+1)^{2}}}{\sqrt{x-1}+1}\\\frac{|\sqrt{x-1}+1|}{\sqrt{x-1}+1}\\we..know..that..\sqrt{x-1}\geq0$

$then..\sqrt{x-1}+1\geq0..too\\so: |\sqrt{x-1}+1| = \sqrt{x-1}+1$

$\frac{\sqrt{x-1}+1}{\sqrt{x-1}+1} = 1$

$b.) (\frac{\sqrt{2}+1}{1+\sqrt{2}+\sqrt{x}} + \frac{\sqrt{2}-1}{1-\sqrt{2}+\sqrt{x}})(\sqrt{x}-\frac{1}{\sqrt{x}+2})\\(\frac{(\sqrt{2}+1)(1-\sqrt{2}+\sqrt{x})+(\sqrt{2}-1)(1+\sqrt{2}+\sqrt{x})}{(1+\sqrt{2}+\sqrt{x})(1-\sqrt{2}+\sqrt{x})})(\sqrt{x}-\frac{1}{\sqrt{x}+2})\\(\frac{2\sqrt{2x}}{x+2\sqrt{x}-1})(\frac{x+2\sqrt{x}-1}{\sqrt{x}+2})\\(\frac{2\sqrt{2x}}{\sqrt{x}+2}})$