Question

Помогите пожалуйста!!!!! дам 50б

Answer 1

$1)\ \ y=3\, lnx-4x^3+\dfrac{2}{x}-3\sqrt{x}\\\\y'=\dfrac{3}{x}-12x^2-\dfrac{2}{x^2}-\dfrac{3}{2\sqrt{x}}\\\\\\2)\ \ y=15\, cos\dfrac{x}{3}\ \ ,\ \ \ \ y'=-\dfrac{15}{3}\, sin\dfrac{x}{3}=-5\, sin\dfrac{x}{3}\\\\\\3)\ \ \ y=\dfrac{6-x}{4x+3}\\\\y'=\dfrac{-(4x+3)-4\cdot (6-x)}{(4x+3)^2}=\dfrac{-27}{(4x+3)^2}$