Question

Помните срочно!!!!!!!!!!​

Answer 1

Ответ:

x=(-1)^k*(-π/4)+πk, k€Z

Объяснение:

√8sinx+2=0

√8sinx=-2

sinx=-2/√8=-2/2√2=-√2/2

x=(-1)^k*(-π/4)+πk, k€Z

Answer 2

$\sqrt{8}Sinx+2=0\\\\2\sqrt{2} Sinx=-2\\\\\sqrt{2}Sinx=-1\\\\Sinx=-\frac{1}{\sqrt{2}}\\\\x=(-1)^{n}arc Sin(-\frac{1}{\sqrt{2}})+\pi n,n\in Z \\\\x=(-1)^{n+1}arc Sin\frac{1}{\sqrt{2}}+\pi n,n\in Z\\\\x=(-1)^{n+1}\frac{\pi }{4}+\pi n,n\in Z\\\\Otvet:\boxed{(-1)^{n+1}\frac{\pi }{4}+\pi n,n\in Z}$