Question

найти предел .............................

Answer 1

$\lim\limits _{x \to 4}\dfrac{\sqrt{2x+1}-3}{\sqrt{2x-1}-\sqrt2}=\Big[\ \dfrac{\sqrt{2\cdot 4+1}-3}{\sqrt{2\cdot 4-1}-\sqrt2}=\dfrac{0}{\sqrt7-\sqrt2}\ \Big]=\dfrac{0}{const}=0$