Question

Решите неравенство 1/3<3^(3+х)<9

Answer 1

$\frac{1}{3} < {3}^{3 + x} < 9 \\ {3}^{ - 1} < {3}^{3 + x} < {3}^{2} \\ - 1 < 3 + x < 2 \\ - 4 < x < - 1$