Question

решите уравнение
4х/х²+4х+4 - х-2/х²+2х=1/х​

Answer 1

$\frac{4x}{ {x}^{2} + 4x + 4} - \frac{x - 2}{ {x}^{2} + 2x} = \frac{1}{x}$

$\frac{4x}{ {(x + 2)}^{2} } - \frac{x - 2}{ x \times (x + 2)} = \frac{1}{x}$

$\frac{4x \times x - ((x - 2)(x + 2))}{x \times {(x + 2)}^{2} } - \frac{1 \times {(x + 2)}^{2} }{x \times {(x + 2)}^{2} } = 0$

$\frac{4 {x}^{2} - ( {x}^{2} - 4) - {(x + 2)}^{2} } {x \times {(x + 2)}^{2} } = 0$

$\frac{4 {x}^{2} - {x}^{2} + 4 - {x}^{2} - 4x - 4 }{x \times {(x + 2)}^{2} } = 0$

$\frac{2 {x}^{2} - 4x }{x \times {(x + 2)}^{2} } = 0$

2х²-4х=0

2х*(х-2)=0

2х=0

х = 0

х-2=0

х=2

х*(х+2)²≠0

х≠0

(х+2)²≠0

х+2≠0

х≠ -2

Ответ: х = 2