Question

Помогите пожалуйста, срочно ​

Answer 1

$x^{2} +\frac{14}{x}=7x+4-\frac{4}{x^{2}}\\\\x^{2}+\frac{14}{x}-7x-4+\frac{4}{x^{2}}=0\\\\(x^{2}-4+\frac{4}{x^{2}})-(7x-\frac{14}{x})=0\\\\(x-\frac{2}{x})^{2}-7(x-\frac{2}{x})=0\\\\(x-\frac{2}{x})(x-\frac{2}{x}-7)=0\\\\1)x-\frac{2}{x}=0\\\\x^{2} -2=0;x\neq 0\\\\x^{2}=2\\\\x_{1,2}=\pm \sqrt{2}\\\\2)x-\frac{2}{x}-7=0\\\\x^{2}-7x-2=0;x\neq0\\\\D=(-7)^{2}-4*(-2)=49+8=57\\\\x_{3} =\frac{7-\sqrt{57}}{2}\\\\x_{4} =\frac{7+\sqrt{57}}{2}$

Ответ : произведение корней равно : (- 2) *  (- 2) = 4