Question

С рисунками и тп!!! СРОЧНО

Answer 1

а. $tg ( 4*arccos\frac{\sqrt{2} }{2} - arctg (-1) ) = tg ( 4*\frac{\pi }{4} - (- \frac{\pi }{4})) = tg (\pi +\frac{\pi }{4}) = tg \frac{\pi }{4} = 1$

c. tg 2x - √3 = 0

tg 2x = √3

2x = arctg √3 + пn , n ∈ Z

$2x = \frac{ \pi }{3} + \pi n$ , n ∈ Z | : 2

$x = \frac{\pi }{6} + \frac{\pi n }{2}$ , n ∈ Z