Question

Через дискриминант х^2-2х-6=0

Answer 1

$x^{2} -2x-6=0\\\\D=(-2)^{2}-4*(-6)=4+24=28=(2\sqrt{7})^{2}\\\\x_{1}=\frac{2-2\sqrt{7}}{2}=1-\sqrt{7}\\\\x_{2}=\frac{2+2\sqrt{7}}{2} =1+\sqrt{7}\\\\Otvet:\boxed{1-\sqrt{7} ;1+\sqrt{7}}$

Answer 2

Ответ:

$x^2-2x-6=0\\D = b^2 - 4ac = 4 - 4 \times (-6) = 28\\x_1 = \frac{2 + \sqrt{28}}{2} = 1 + \sqrt{7}; \ x_2 = \frac{2 - \sqrt{28}}{2} = 1 - \sqrt{7};$