Question

Вычислите: 3^(2-3√3) * 27^√3

Answer 1

$3^{2-3\sqrt{3}}*27^{\sqrt{3}}=3^{2-3\sqrt{3}}*(3^{3})^{\sqrt{3}}=3^{2-3\sqrt{3}}*3^{3\sqrt{3}}=3^{2-3\sqrt{3}+3\sqrt{3}}=3^{2}=9\\\\Otvet:\boxed{9}$