Question

Cистема уравнений - 40Б

Answer 1

$+\left \{ {{2^{5x+3y}-\sqrt{2x+7y}=2} \atop {-2^{5x+3y}+3\sqrt{2x+7y}=10}} \right.\\-----------\\ 2\sqrt{2x+7y}=12\\\\\sqrt{2x+7y}=6\\\\2x+7y=36\\\\x+3,5y=18\Rightarrow x=18-3,5y\\\\\\2^{5*(18-3,5y)+3y}-\sqrt{36}=2\\\\2^{90-17,5y+3y}-6=2\\\\2^{90-14,5y}=8\\\\2^{90-14,5y}=2^{3}\\\\90-14,5y=3\\\\-14,5y=-87\\\\y=6\\\\x=18-3,5*6=18-21=-3\\\\Otvet:\boxed{(-3;6)}$