Question

Решите неравенство
0,5^x < 3

Answer 1

 $0,5^{x}<3\\3=0,5^{log_{0,5}{3}}; ; [a^{log_{a}{b}}=b]\\0,5^{x}<0,5^{log_{0,5}{3}}\\Tak; ; kak; ; 0,5<1,; to; x>log_{0,5}3\\log_{0,5}3=log_{2^{-1}}3=-log_2{3}\\x>-log_2{3}$