Question

3. Решить неравенство: sin2x < 1/2

Answer 1

$sin2x<\dfrac{1}{2}\\\\\dfrac{5\pi}{6}+2\pi n<2x<\dfrac{13\pi }{6}+2\pi n\ ,\ n\in Z\\\\\dfrac{5\pi }{12}<x<\dfrac{13\pi }{12}+\pi n\ ,\ n\in Z$