Question

Сократить дробь...........​

Answer 1

$\frac{18^{n+3} }{3^{2n+5}*2^{n-2}}=\frac{(3^{2}*2)^{n+3}}{3^{2n+5}*2^{n-2}}=\frac{3^{2n+6}*2^{n+3}}{3^{2n+5}*2^{n-2}} =3^{2n+6-2n-5}*2^{n+3-n+2}=3*2^{5}=3*32=96\\\\Otvet:\boxed{96}$