Question

у(х)=сosx(sinx+1) найти y'(x) ​

Answer 1

Объяснение:

y'(x) = (cos x *(sin x + 1))' = (cos x)' * (sin x + 1) + cos x * (sin x + 1)' = -sin x* (sin x + 1) + cos^2 x = -sin^2 x - sin x + cos^2 x = cos 2x - sin x

Ответ: y'(x) = cos 2x - sin x.