Question

Алгебра 11 класс. Срочно

Answer 1

$\displaystyle\\\int\limits^2_1 {3x^2+4x-\frac{2}{x^2} } \, dx =(3*\frac{x^3}{3}+4*\frac{x^2}{2}-2*(-\frac{1}{x}))\mid^2_1=(x^3+2x^2+\frac{2}{x})\mid^2_1=\\\\\\=(2^3+2*2^2+\frac{2}{2}-(1^3+2*1^2+\frac{2}{1}))=8+8+1-(1+2+2)=\\\\\\=17-5=12$