Question

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Answer 1

Ответ:

$(5 \frac{5}{6} + 8 \frac{2}{9} ) \div 25.3 - 3 \frac{1}{9} + 1.5 \div \frac{27}{28} = - 1 \\ 1) (5 \frac{5}{6} + 8 \frac{2}{9} ) = \frac{35}{6} + \frac{74}{9} = \frac{105 + 148}{18} = \frac{253}{18} \\ 2) \frac{253}{18} \div 25.3 = \frac{253}{18} \div \frac{253}{10} = \frac{253}{18} \times \frac{10}{253} = \frac{5}{9} \\ 3)1.5 \div \frac{27}{28} = \frac{15}{10} \div \frac{27}{28} = \frac{15}{10} \times \frac{28}{27} = \frac{14}{9} \\ 4) \frac{5}{9} - 3 \frac{1}{9} = \frac{5}{9} - \frac{28}{9} = \frac{5 - 28}{9} = - \frac{23}{9} \\ 5) - \frac{23}{9} + \frac{14}{9} = \frac{ - 23 + 14}{9} = - \frac{9}{9} = - 1$

$117.5 \times \frac{4}{47} - 11 \frac{2}{3} + (10 \frac{2}{25} - 8 \frac{7}{15} ) \div \frac{11}{45} =4 \frac{14}{15} \\ 1)10 \frac{2}{25} - 8 \frac{7}{15} = \frac{252}{25} - \frac{127}{15} = \frac{756 - 635}{75} = \frac{121}{75} \\ 2)117.5 \times \frac{4}{47} = \frac{1175}{10} \times \frac{4}{47} = \frac{235}{2} \times \frac{4}{47} = 10 \\ 3) \frac{121}{75} \div \frac{11}{45} = \frac{121}{75} \times \frac{45}{11} = \frac{33}{5} \\ 4)10 - 11 \frac{2}{3} = \frac{30}{3} - \frac{35}{3} = \frac{30 - 35}{3} = - \frac{5}{3} \\ 5) - \frac{5}{3} + \frac{33}{5} = \frac{ - 25 + 99}{15} = \frac{74}{15} = 4 \frac{14}{15}$