Question

Помогите, пожалуйста!!!!

Answer 1

$2^{log_{2}^{2}x }+x^{log_{2}x^{2}}=6\\\\(2^{log_{2}x })^{log_{2}x }+(x^{log_{2}x })^{2}=6\\\\x^{log_{2}x }+(x^{log_{2}x})^{2}=6\\\\x^{log_{2}x }=m,m>0\\\\m^{2}+m-6=0\\\\m_{1}=2\\\\m_{2}=-3-neyd \\\\x^{log_{2}x }=2\\\\log_{2}x^{log_{2}x }=log_{2}2\\\\log_{2}^{2}x=1\\\\1)log_{2} x=1\\\\x_{1} =2\\\\2)log_{2}x=-1\\\\x_{2}=0,5$

$Otvet:\boxed{2;0,5}$