Question

иррациональные уравнения

Answer 1

Ответ:

$\sqrt{ {x}^{2} + 2x + 10} = 2x - 1 \\ {x}^{2} + 2x + 10 = 4 {x}^{2} - 4x + 1 \\3 {x}^{2} - 6x - 9 = 0 \\ {x}^{2} - 2x - 3 = 0 \\ x1 = - 1 \\ x2 = 3 \\ \\ \sqrt{2x - 1} = 2 - x \\ 2x - 1 = 4 - 4x + {x}^{2} \\ {x}^{2} - 6x + 5 = 0 \\ x1 = 1 \\ x2 = 5 \\ \\ \sqrt{3x - 2} = 2 - x \\ 3x - 2 = 4 - 4x + {x}^{2} \\ {x}^{2} - 7x + 6 = 0 \\ x1 = 1 \\ x2 = 6$