Question

помогите с алгеброй, пожалуйста! 40 баллов!!!!

Answer 1

Ответ:

3)

$f(x) = 6 {x}^{4} - 4 {x}^{6} \\ 0 = 6 {x}^{4} - 4 {x}^{6} \\ x1 = - \frac{ \sqrt{6} }{2} \\ x2 = 0 \\ x3 = \frac{ \sqrt{6} }{2}$

2)

$f(x) = {x}^{3} + 6 {x}^{2} + 9x \\ 0 = {x}^{3} + 6 {x}^{2} + 9x \\ x1 = - 3 \\ x2 = 0$

1)

$f(x) = 3x - {x}^{2} \\ 0 = 3x - {x}^{2} \\ x1 = 0 \\ x2 = 3$