Question

Даю 90 балов помогите
номер 6,7,8

Answer 1

6)
$16 {a}^{2} - 2.4ab + x = 16 {a}^{2} - 2 \times (4a) \times (0.3b) + 0.09 {b}^{2} ={ (4a - 0.3b) }^{2}$
Ответ: А) 0,09b^2


7)
${a}^{2} + x + \frac{1}{4} {b}^{2} = {a}^{2} + 2 \times a \times (\frac{1}{2} b) + \frac{1}{4} {b}^{2} = {a}^{2} + ab + \frac{1}{4} {b}^{2} = {(a + \frac{1}{2} b) }^{2}$
Ответ: С) аb

8)
$4 {a}^{2} + x + 0.01 {b}^{2} = 4 {a}^{2} + 2 \times (2a) \times (0.1b) + 0.01 {b}^{2} = 4 {a}^{2} + 0.4ab + 0.01 {b}^{2} = {(2a + 0.1b)}^{2}$
Ответ: C) 0,4ab