Question

Найти у'(1),якщо y=2✓x-3/x2​

Answer 1

Ответ:

$y=2\sqrt{x}-\dfrac{3}{x^2}\ \ ,\ \ \ x_0=1\\\\y'=\dfrac{2}{2\sqrt{x}}-\dfrac{-3\cdot 2x}{x^4}=\dfrac{1}{\sqrt{x}}-\dfrac{6}{x^3}\\\\\\y'(1)=1-6=-5$