Question

Помогите с 1 и 2 вопросом, пожалуйста!!!

Answer 1

Пошаговое объяснение:

$1.\\1)\sqrt{225}=\sqrt{15^{2}}=15\\\\ 2)\sqrt{\frac{49}{4}}=\frac{\sqrt{49} }{\sqrt{4} } =\frac{\sqrt{7^{2}} }{\sqrt{2^{2}}}=\frac{7}{2}=3.5\\\\3)\sqrt{6.76}=\sqrt{2.6^{2}}=2.6\\\\ 4)\sqrt{7\frac{1}{9}}=\sqrt{\frac{64}{9}}=\frac{\sqrt{64}}{\sqrt{9}}=\frac{\sqrt{8^{2}} }{\sqrt{3^{2}}}=\frac{8}{3}\\\\ 5)\sqrt{16.81}=\sqrt{4.1^{2}}=4.1\\\\ 6)\sqrt{1225}=\sqrt{35^{2}}=35$

$2.\\1)\sqrt{49} =\sqrt{7^{2}}=7\\ 7\neq -7\\\\2)\sqrt{1.69} =\sqrt{1.3^{2}}=1.3\\1.3\neq -1.3\\\\3)\sqrt{(-9)^{2}}=\sqrt{81}=\sqrt{9^{2}}=9\\ 9\neq -9\\\\4)\sqrt{(-7.8)^{2}}=\sqrt{60.84}=\sqrt{7.8^{2}}=7.8\\ 7.8\neq -7.8$