Question

logs(x-10)=2+logs2 ;)

Answer 1

Ответ:

Объяснение:

$log_s(x-10)=2+log_s2\\log_s(x-10)=2*log_s5+log_s2\\log_s(x-10)=log_s5^2+log_s2\\log_s(x-10)=log_s25+log_s2\\log_s(x-10)=log_s(25*2)\\log_s(x-10)=log_s50\\x-10=50\\x=60.$