Question

х2+5/3-1=(2х+1)(2х-1)

Answer 1

Ответ:

$x {}^{2} + 1 \frac{2}{3} - 1 = {4x}^{2} - 1 \\ {x}^{2} + \frac{2}{3} - 4 {x}^{2} + 1 = 0 \\ - 3 {x}^{2} + 1 \frac{2}{3} = 0$

$- 3x {}^{2} = 0 - 1 \frac{2}{3} \\ - 3 {x}^{2} = - 1 \frac{2}{3}$

${x}^{2} = - 1 \frac{2}{3} \div ( - 3) \\ {x}^{2} = \frac{5}{3} \times \frac{1}{3} \\ {x}^{2} = \frac{5}{9}$

$x1 = \frac{ \sqrt{5} }{3}$

$x2 = - \frac{ \sqrt{5} }{3}$