Предмет: Химия, автор: Эвелина717

Методом электронного баланса найти коэффициенты в уравнении реакции. Укажите окислитель и восстановитель.
K2Cr2O7 + K2S + H2O → Cr (OH) 3 + S + KOH

Ответы

Автор ответа: Egorweek

1

Ответ:

K2Cr2O7 + K2S + 5H2O = 2Cr(OH)3 + S + 4KOH

Объяснение:

Cr - окислитель

S - восстановитель

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