Предмет: Физика, автор: tralalal

Двигун за 200с виконав роботу 400 кДж. Яка потужність двигуна?

Ответы

Автор ответа: Ruuі
0

Ответ:

Дано

t=200 c

A=400 000 Дж

N-?

Решение

N=A/t

N=400 000 Дж/200 с=2000 Вт=2 кВт

Ответ :N=2 кВт

Автор ответа: artcolnik
0

Ответ:N=20

Объяснение: 400кДж=4000Дж

N=4000Дж/200с=20Вт

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