Предмет: Алгебра, автор: vlados200682

Сократите дробь..................... ​

Приложения:

ludmilakuzua: 2?
vlados200682: я решил, там корень из a+2
mugalim13: Молодец!
mugalim13: Если нужно решение, смотрите ниже.

Ответы

Автор ответа: mugalim13
1

Ответ:

№ 1.  a^{3}

№ 2. (\sqrt{a} +2)

Объяснение:

№ 1.  

1)     (a^{-2} )^{6} = a^{-12} \\\\\\2)     a^{-12} / a^{-15} = a^{-12-(-15)}  = a^{3}

№ 2

\frac{a\sqrt{a}+8}{a-2\sqrt{a}+4}\\

Рассмотрим числитель:

{a\sqrt{a}+8} = (\sqrt{a}^3 + 2^3)  =  (\sqrt{a} +2)  (a - 2\sqrt{a} + 4 )

Второй множитель и знаменатель равны, значит, мы можем сократить эту дробь в (a - 2\sqrt{a} + 4 ) раз.

Остаётся (\sqrt{a} +2). Это ответ.

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